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Umnica [9.8K]
3 years ago
9

Can someone check this?

Mathematics
2 answers:
hoa [83]3 years ago
8 0
It is the last answer
antoniya [11.8K]3 years ago
7 0
I believe d is the correct answer
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Find the measure of angle A
blagie [28]

Answer:

43°

Step-by-step explanation:

(x + 53)° + (x + 74)° + 73° = 180°

(x + 53 + x + 74)° = 180° - 73°

(2x + 127)° = 107°

2x + 127 = 107

2x = 107 - 127

2x = - 20

x = - 20/2

x = - 10

m\angle A = (x +53)\degree \\\\m\angle A = (-10 +53)\degree \\\\m\angle A = 43\degree \\\\

4 0
3 years ago
1. (05.06 MC)
adoni [48]
Part A: it is linear because it is not curving and it consists of straight lines.

Part B: in side A it is increasing because it has a positive slope. In side b it is constant because the slope is 0 since it is straight. Finally, side C is decreasing because the slope is negative.

Part C: during side A the ant is crawling out of the hole in 2 seconds. After that, the ant stops for 2 more seconds as shown in side B. Then, he crawls back into the hole as shown by the decrease in distance due to the slope.

Hope this helps!!!
8 0
3 years ago
Which set of steps shows the solution to the equation 3y = -9?
Lisa [10]

Answer:

see below

Step-by-step explanation:

3y = -9

Divide each side by 3

3y/3 = -9/3

y = -3

8 0
3 years ago
Read 2 more answers
**GIVING OUT BRAINLIEST PLEASE HELP***
OLga [1]

Answer:

n is less than or equal to: 10

Step-by-step explanation:

10n+20=120

subtract 20

10n=100

divide by 10

n=10

7 0
3 years ago
Read 2 more answers
Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0
3 years ago
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