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saveliy_v [14]
3 years ago
8

Which of the following does not have triangular faces?

Mathematics
2 answers:
svp [43]3 years ago
5 0

Answer:

Step-by-step explanation:

Answer "A"

Dodecahedron

Alika [10]3 years ago
5 0

Answer:

Hexahedron is the right answer

Step-by-step explanation:

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100.7 x 0.009 (basic math im in 5th grade)
pogonyaev

Answer

0.9063

Step-by-step explanation:

(100.7)*(0.009)

3 0
3 years ago
10.9 + (-15.6) + 2.1 write as a decimal​
Delvig [45]

Answer:

-2.6

Step-by-step explanation:

10.9 + (-15.6) becomes 10.9 - 15.6 which equals -4.7. The last step is to add the 2.1 to the -4.7: -4.7 + 2.1 = -2.6

Therefore the answer is -2.6

5 0
3 years ago
13 and 15<br><br>solve each problem by graphing and slope intercept​
mylen [45]

Answer: The answers are 13. (A) and 14. (B).

Step-by-step explanation: The calculations are as follows:

(13) The given equations are

y=-\dfrac{3}{8}x-6,\\\\\\y=-\dfrac{13}{8}x+4.

In the attached figure (a), these two lines are drawn. We can see that The lines intersect at the point P(8, -9). So, the solution to the pair of equations is (8, -9).

Thus, the correct option is (A).

(14) The given equations are

y=-\dfrac{1}{7}x-1,\\\\\\y=-x+5.

In the attached figure (b), these two lines are drawn. We can see that The lines intersect at the point Q(7, -2). So, the solution to the pair of equations is (7, -2).

Thus, the correct option is (B).

7 0
3 years ago
2x+3/4(4x+16)=7 <br> I need help finding x.. I don’t know how to do these problems with fractions :(
KIM [24]

Answer:

x=-1

Step-by-step explanation:

2x+3/4(4x+16)=7

2x+(3x12)=7--->distributive property

2x+3x+12=7

5x+12=7--->addition property

5x=-5--->subtraction peroperty

x= -1---?division property

5 0
2 years ago
Pythagorean theorem to determine if a triangle with sides 2 ft,5ft,4ft is a right triangle
Delvig [45]
a^2 + b^2 = c^2

2^2 + 4^2 = 5^2

4 + 16 = 25

20 = 25

Since 20 = 25 is clearly a false statement, the three side lengths 2 ft, 4 ft, and 5 ft do not form a right triangle.
4 0
3 years ago
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