Answer:
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Step-by-step explanation:
step 1
Find the equation of the solid blue line
Let
A(0,-2), B(1,1)
Find the slope of AB
m=(1+2)/(1-0)=3
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=3
b=-2 - ----> the point A is the y-intercept
substitute
y=3x-2 - -----> equation of the solid blue line
The solution of the inequality is the shaded area above the solid line
therefore
The first inequality is
y\geq 3x-2
C(0,2), D(5,1)
step 2
Find the equation of the dashed red line
Let
Find the slope of CD
m=(1-2)/(5-0)=-1/5
The equation of the line into slope intercept form is equal to
y=mx+b
we have
m=-1/5
b=2 ----> the point C is the y-intercept
substitute
y=-(1/5)x+2 -----> equation of the dashed red line
The solution of the inequality is the shaded area below the dashed line
therefore
The second inequality is
y<-(1/5)x+2
The system of inequalities is
y\geq 3x-2
y<-(1/5)x+2
Answer:
The sum is
Step-by-step explanation:
Assuming we are finding the sum of :
3e + 7 - e and 2e + 10 + 2e -3
Then we set up the addition as follows:
We group similar try to get:
We now combine the similar terms to obtain:
Therefore the sum is
What is the Mean, Q1, Med, Q3, and max of the numbers [1,1,3,3,3,9,10,10,11,11,12,12,12,15]
Naddik [55]
Answer:
Hi! The answer is Mean: 8.1, Q1: 3, Med: 10, Q3: 12, Max: 14
Step-by-step explanation:
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