Answer:
All of the above individuals demonstrate these errors
Explanation:
Answer:
0.483
Explanation:
The given population is in Hardy-Weinberg equilibrium. If the gene has two alleles, the sum total of the frequencies of these two alleles will be one.
Therefore, the total of the frequency of allele B and frequency of allele b will be 1. f(B) + f(b)=1
If the frequency of allele "B" is 0.59, then the frequency of allele "b" will be=1-0.59= 0.41
The frequency of heterozygous genotype in the population= 2pq
p= frequency of the dominant allele
q= frequency of the recessive allele
So, 2pq= 2 x 0.59 x 0.41 = 0.483
You would most likely find fish, such as rainbow trout, in the limnetic zone.
An enzyme possesses different kinetics for different substrates as a result of this different products are formed.
Discussion:
- Multi-substrate reactions are governed by intricate rate equations that specify how and in what order the substrates bind. If substrate B is altered while the amount of substrate A remains constant, the study of these reactions becomes considerably easier. The enzyme behaves exactly like a single-substrate enzyme in these circumstances, and a plot of v by [S] yields the actual KM and Vmax constants for substrate B.
- These results can be utilized to determine the reaction's mechanism if a series of such measurements are carried out at various fixed concentrations of A. There are two different sorts of mechanisms for an enzyme that accepts two substrates, A and B, and converts them into two products, P and Q: ternary complex and ping-pong.
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