-(3/(2y+12))+2=-(8/(y+6)
1 answer:
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The volume of a cone is
V = (1/3) π r² h
where r = radius of the base
h = the height.
The volume of the frustum is
(1/3)π(7.5²)(11+8) - (1/3)π(3.5²)(8)
=(1/3)π(7.5²)(19) - (1/3)π(3.5²)(8)
The 3rd choice is the correct answer.
Answer:
V = (1/3) π r² h
where r = radius of the base
h = the height.
The volume of the frustum is
(1/3)π(7.5²)(11+8) - (1/3)π(3.5²)(8)
=(1/3)π(7.5²)(19) - (1/3)π(3.5²)(8)
The 3rd choice is the correct answer.
Answer: