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saw5 [17]
3 years ago
5

Super Super dumb Easy question lol Does this count as an equation 60.50 × .20 = x

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
4 0
Yes i’m pretty sure it counts
Ipatiy [6.2K]3 years ago
4 0

Answer:

Yes it does count as a equation.

Please mark as brainliest.

Step-by-step explanation:

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2x + y = -4<br> 5x - 3y = 1<br><br> Solve with elimination method
Ivanshal [37]

Answer:

For the first equation the answer for "X" will be,

x =  \frac{ - 4 - y}{2}

if you want me to solve for y instead then the answer will be,

y =  - 4 - 2x

for the second equation the answer for "X" will be,

x =  \frac{1 + 3y}{5}

If you want me to solve for y instead then the answer will be,

y =  -  \frac{1 - 5x}{3}

3 0
3 years ago
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An animal shelter houses dogs, cats, and rabbits. There are 126 animals at the shelter. Of the animals, one-third are cats. Thre
Furkat [3]

Answer:

21

Step-by-step explanation:

126/3=42

126-42=84

84/4=21

63 are dogs

42 are cats

and 21 are rabbits

4 0
3 years ago
If the annual property tax is $2400.What is the monthly property tax?
anygoal [31]

Answer:

$200.00

Step-by-step explanation:

$2400÷12=$200.

5 0
3 years ago
Solve for x -6 &gt;_ 10 - 4x
Otrada [13]

We are given this inequality,

-6\geq10-4x

We will follow these steps to solve it:

Step 1:

First let us bring 10 to the left side.

10 is in addition on right, so we apply opposite operation of addition that is subtracting 10 from left side, we get

-6-10\geq-4x

-16\geq-4x

Step 2:

Next we have to eliminate -4 which is in multiplication with x on the right side.

So applying opposite operation of multiplication that is dividing both sides by -4.

We have to consider here that when we divide or multiply with a negative the sign of inequality reverses, that is ≥ becomes ≤ and vice versa.

\frac{-16}{-4}\leq x

x≥4

Answer is last option x≥4.

6 0
3 years ago
Help me throughout this question please!!!!!!​
vagabundo [1.1K]

\cos(2A)=\cos^2 A-\sin^2A=(\cos A+ \sin A)(\cos A-\sin A)

substitute the second term in LHS to get

{ (\cos A - \sin A)^2 \over \cos(2A))}

expand the square, \frac{1-2\sin A \cos A}{\cos 2A}= \sec2A- \tan 2A

(\sin (2\theta)=2 \sin\theta\cos\theta)

4 0
3 years ago
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