The volume and surface area of the pyramid will be 392 / 3 cubic units and 189 square units. Then the correct option is A.
The complete question is attached below.
<h3>What is the volume and surface area of the pyramid? </h3>
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
Then the volume of the pyramid will be
V = (L × B × H) / 3
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
Then the volume will be
V = (7 × 7 × 8) / 3
V = 392/3 cubic units
Then the surface area will be
SA = 2(1/2 × 7 × 10) + 2(1/2 × 7 × 10) + (7 × 7)
SA = 189 square units
Then the correct option is A.
More about the volume and surface area of the pyramid link is given below.
brainly.com/question/23302816
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I hope this helps you
(-)×(-)=+
-(-16)
+16
Answer:

Step-by-step explanation:




<h3>Hope it is helpful....</h3>
Answer:
Step-by-step explanation:
<u>Given</u>
- DE = 3x + 2, EF = x + 5, DF = 23
<u>As per segment addition postulate</u>
<u>Substituting values:</u>
- 3x + 2 + x + 5 = 23
- 4x + 7 = 23
- 4x = 16
- x = 4
Answer:
D. 0.74.
Step-by-step explanation:
It is a BINOMIAL trial, which means that there are only two outcomes: either success, or failure.
So, if the probability of success is 0.26, the probability of failure will be 1 - 0.26 = 0.74.
Hope this helps!