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guajiro [1.7K]
3 years ago
6

What is 737.303 - 43.866

Mathematics
1 answer:
Tom [10]3 years ago
8 0
Solve by subtracting
737.303-43.866=693.437
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Lin read 3/8 of a magazine article on Monday and 1/4 of the article on Tuesday. What fraction of the article did she read on Mon
larisa [96]
<span>Lin read 5/8 of the total article on Monday and Tuesday. Lin read 3/8 of the article on Monday. Lin read 1/4 of the article on Tuesday. 1/4 can be converted into 2/8. 2/8 plus 3/8 is 5/8, which cannot be further simplified.</span>
8 0
3 years ago
What is 32⋅(12)x+1=2x−14?
vazorg [7]

Answer:

x=-\frac{15}{382}

Step-by-step explanation:

32 × 12x + 1 = 2x - 14

384x + 1 = 2x - 14

384x + 1 - 1 = 2x - 14 - 1

384x = 2x - 15

384x - 2x = 2x - 2x - 15

382x = - 15

382x ÷ 382 = - 15 ÷ 382

x=-\frac{15}{382}

5 0
3 years ago
You open a brand-new savings account January 1, 2021. Every paycheck you earn you deposit $25 into a savings account, and you ne
timofeeve [1]

The amount of money that you will have at the end of the year from your brand-new savings account is $600.69.

<h3>What is future value?</h3>

The future value is the value of periodic cash flows in the future.  It can be computed using an online finance calculator as follows:

<h3>Data and Calculations:</h3>

N (# of periods) = 24 (12 X 2)

I/Y (Interest per year) = 0.12% (0.01% X 12)

PV (Present Value) = $0

PMT (Periodic Payment) = $25

Results:

FV = $600.69

Sum of all periodic payments = $600.00 ($25 X 24)

Total Interest = $0.69

Thus, the amount of money that you will have at the end of the year from your brand-new savings account is $600.69.

Learn more about future values at brainly.com/question/24703884

6 0
2 years ago
3 + x ≥ 12 solve the inequality
kherson [118]
3 + x \geq 12 \\ \\ x \geq 12 - 3 \\ \\ x \geq 9 \\ \\

You just subtract 3 from each side and then simplify (12 - 3) which is 9. 

The final result is: x ≥ 9.

8 0
3 years ago
Explain how to derive a formula for sin(A - B + C)
Akimi4 [234]

\textit{Sum and Difference Identities} \\\\ sin(\alpha - \beta)=sin(\alpha)cos(\beta)- cos(\alpha)sin(\beta) \\\\ cos(\alpha - \beta)= cos(\alpha)cos(\beta) + sin(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(A-B+C)\implies sin[~(\stackrel{Z}{A-B})~+C]\implies sin(Z+C) \\\\\\ sin(Z)cos(C)+cos(Z)sin(C)\implies sin(A-B)cos(C)+cos(A-B)sin(C) \\\\[-0.35em] ~\dotfill\\\\ \textit{and since we know that}\\\\ sin(A-B)\implies sin(A)cos(B)-cos(A)sin(B)

cos(A-B)\implies cos(A)cos(B)+sin(A)sin(B)\\\\ then \\\\[-0.35em] ~\dotfill\\\\\ [sin(A)cos(B)-cos(A)sin(B)]cos(C)+[cos(A)cos(B)+sin(A)sin(B)]sin(C) \\\\\\ ~\hfill \begin{array}{cllll} sin(A)cos(B)cos(C)-cos(A)sin(B)cos(C)\\\\ +\\\\ cos(A)cos(B)sin(C)+sin(A)sin(B)sin(C) \end{array}~\hfill

6 0
2 years ago
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