Please hurry this is 7th grade math

Please help me with this answer<br><br> (Links and spam answers will be reported)

Angelina_Jolie [31]

Answer:

area if circle =πr²=π6²=36πmm²

5 0

2 years ago

You are flying a kite on a line that is 350 feet long. Let's suppose the line is perfectly straight (it never really is) and it

aliina [53]

Answer:

We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.

And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.

This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°

A = 90° - 65° = 25°

Then the altitude of the kite is the adjacent cathetus to this angle.

We can use the relation:

sin(A) = Adjacent cathetus/hypotenuse.

Sin(25°) = X/350ft

Sin(25°)*350ft = X = 147.9m

4 0

3 years ago

Can you please help me with the three questions on there, they all are different.

Vesnalui [34]

1. A=(0,4)
2. B=(4,1)
3. Slope=-3/4

3 0

2 years ago

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The circumference of a circle exceeds the radius by 74 cm. Find the radius of the circle.

saw5 [17]

Answer:

14 cm.

Step-by-step explanation:

Let the radius of the circle = r cm.

Then circumference of circle = 2 π r.

Since circumference exceeds the radius by 74 cm

Therefore, according to the question,

$\sf \:2 π r = r+ 74$

$\sf \: = > 2 \times \frac{22}{7} \times r = r \: + 74$

$\sf \: = > \frac{44r}{7} -r = 74$

$\sf \: = > \frac{44r - 7r}{7} = 74$

$\sf \: = > \frac{37r}{7} = 74$

$\sf \: = > r = \frac{7 \times 74}{37}$

$\sf \: = > r = 14$

Hence, the radius of the circle is 14 cm.

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3 0

2 years ago

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

Hope this wasn't too confusing! I'll answer any questions.

8 0

2 years ago

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