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crimeas [40]
3 years ago
6

A rectangular painting canvas has the dimensions of 22 by 23 inches. Find the area, in square inches, of the painting. Use the f

ormula, area = length * width
Mathematics
2 answers:
Ulleksa [173]3 years ago
4 0

Answer:

506 square inches

Step-by-step explanation:

length=22 inches

breadth=23 inches

area=length *breadth

area=22*23=506 squareinches

Kisachek [45]3 years ago
4 0

Answer:

506 inches

Step-by-step explanation:

22 times 23 equals 506 inches.

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F(1) = -3<br> f(n) = 2 · f(n − 1) +1<br> f(2)=
raketka [301]

Answer:

-5

Step-by-step explanation:

f(2) = 2 * f(1) + 1

f(2) = 2 * -3 + 1

f(2) = -6 + 1

f(2) = -5

6 0
3 years ago
What is the definition of a ray
Elan Coil [88]
Mathematically, a ray is a portion of a line which starts at a point and goes off in a particular direction to infinity.


4 0
3 years ago
In gym class students were asked to form six equal groups. If there were 18 students in each group, then how many total students
Contact [7]

Answer:108

Step-by-step explanation:

18 times 6 is 108

7 0
2 years ago
Find the standard form of the equation of the parabola with the given characteristics. Vertex: (-6, 1); focus: (-6, 0)
GREYUIT [131]

Answer: (x+6)^2=-4(y-1)

Step-by-step explanation:

Given

Vertex of the parabola (-6,1)

Focus of the parabola (-6,0)

As the x coordinate of vertex and focus is same and focus lie below the vertex, therefore the parabola is the type of

(x+6)^2=-4a(y-1)

distance between Vertex and focus is 1 unit

\therefore a=1

Parabola becomes

\Rightarrow (x+6)^2=-4(y-1)

8 0
3 years ago
Choose one of the factors of 500x3 + 108y18
sammy [17]

Answer:

Option C

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).

Step-by-step explanation:

Given: 500x^3 +108y^\left (18\right )

the common factor from 500x^3 and 108y^\left (18\right ) is 4.

therefore, 4\cdot \left ( 125x^3+27y^\left (18\right ) \right )

4\cdot \left ( (5x)^3+(3y^6)^3 \right))

Now, use the formula for above expression: (a^3+b^3)=(a+b)(a^2-ab+b^2)

here, a=5x and b=3y^6

( (5x)^3+(3y^6)^3 \right))=(5x+3y^6)(25x^2-15xy^6+9y^12)

Therefore, we have

500x^3 +108y^\left (18\right )=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right )  \right )

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).








7 0
3 years ago
Read 2 more answers
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