Answer:E is as far from C as it is from D. So,CE = E-C = (-1-5,0-2) = (-6,-2)So, add that much to E and you getD = E+(E-C) = (-1,0)+(-6,-2) = (-7,-2)
Explanation:
Answer:
The probability that the child will have type blood B equals <u>3/16</u>.
Explanation:
<u>Available data:</u>
- Individuals with the rare Bombay blood phenotype lack both the A and B antigens in individuals and/or are of hh genotype.
- Cross between two parents that are both of I A I B Hh genotype
Cross: IAIB Hh x IAIB Hh
Gametes) IAH, IAh, IBH, IBh
IAH, IAh, IBH, IBh
Punnett square) IAH IAh IBH IBh
IAH IAIAHH IAIAHh IAIBHH IAIBHh
IAh IAIAHh IAIAhh IAIBHh IAIBhh
IBH IAIBHH IAIBHh IBIBHH IBIBHh
IBh IAIBHh IAIBhh IBIBHh IBIBhh
F1) Genotype
- 1/16 IAIA HH
- 2/16 IAIAHh
- 1/16 IAIAhh
- 2/16 IAIBHH
- 4/16 IAIBHh
- 2/16 IAIBhh
- 1/16 IBIBHH
- 2/16 IBIBHh
- 1/16 IBIBhh
Phenotype
- 3/16 Blood type A
- 6/16 Blood type AB
- 3/16 Blood type B
- 3/16 Blood type 0
This is an example of evolution through natural selection. The peppered moths started off with a light color scheme when the industrial revolution started, and they had this to blend into the trees. The better the moths could blend in, the less likely they were to be preyed upon. Once the trees changed colors, the light moths were vulnerable. The months that thrived in this change were the darkly colored moths. These moths then bred and spread their dark color pattern to best fit into the new environment.
