Apply the Pyth Thm twice:
diagonal of base is sqrt(4^2+6^2).
Then the length of diagonal AB is L = [sqrt(4^2+6^2)]^2 + [sqrt(1)]^2
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Answer:
From least to greatest is 2/30, 2/5, 2/4
<em>Hope I Helped</em>
In the figure we have the graphic of this equation. So, the vertex is the maximum of this function. This point means that the maximum <span>daily profit from soccer balls is:
</span>

<span>
And this happens when the </span><span>selling price of each soccer ball is:
</span>

<span>
So if you want to get the best daily profit, this is the price you must sell each soccer ball.</span>
Answer
![12b^{2} \sqrt[3]{2a}](https://tex.z-dn.net/?f=12b%5E%7B2%7D%20%5Csqrt%5B3%5D%7B2a%7D)
Step-by-step explanation: