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Ivan
4 years ago
14

line m passes through point (-2,-1) and is perpendicular to the graph of y=-2/3x+6. Line n is parallel to line m and passes thro

ugh the point (4,-3).What is the equation in slope-intercept form of the line n?
Mathematics
2 answers:
puteri [66]4 years ago
7 0

Answer:

Hello...... here is a solution :

1 -  

Hello:

the   equation of "m" is : y = ax+b

the slope is a : a×(- 2/3) = -1......( perpendicular to a line : y=-2/3x+6 when the slope is -2/3 )

a = 3/2          

the line " n" that passes through (4, - 3) and  parallel to line "m" :  

when the slope is 3/2 ( same slope )

the equation in slope-intercept form of the line" n" is :

 y – (-3)= (3/2)(x – 4)







sergejj [24]4 years ago
4 0

Answer: \bold{y=\dfrac{3}{2}x-9}

<u>Step-by-step explanation:</u>

Line m is perpendicular to y=-\dfrac{2}{3}x+6. Perpendicular means opposite and reciprocal slope, so

m=-\dfrac{2}{3}\ \quad m_\perp=\dfrac{3}{2}

Line n is parallel to Line m. Parallel means same slope, so m=\dfrac{3}{2}


Next, input the point (4, -3) and the slope \bigg(\dfrac{3}{2}\bigg) into the Point-Slope formula: y- y₁ = m(x - x₁)

y - (-3) = \dfrac{3}{2}(x-4)


Now, rewrite the equation in Slope-Intercept form - <em>distribute the slope and solve for "y".</em>

y + 3 = \dfrac{3}{2}x-\dfrac{3}{2}(4)

y + 3 = \dfrac{3}{2}x-6

   y = \dfrac{3}{2}x-9




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The pyramid ABCDE has a square base. the pyramid is 20cm high and each sloping edge measures 30cm. calculate the length of the s
Amanda [17]

Answer:

44.8 cm

Step-by-step explanation:

Vertical height (h) = EM = 20 cm

Slant height (l) = 30 cm

This two heights form a right angle at the interception at the base. Thus, we have a right angle triangle.

The length of the sides of the base = 2 × the base of the right triangle

✔️Use Pythagorean theorem to find the base of the right triangle formed. Thus: c² = a² + b²

a = base of the triangle

b = h = 20 cm

c = l = 30 cm

Plug in the values

30² = a² + 20²

a² = 30² - 20²

a² = 500

a = √500

a = 22.4 cm

✔️length of the sides of the base = 2 × the base of the right triangle

= 2 × a

= 2 × 22.4

= 44.8 cm

8 0
4 years ago
Try me IF you can !!!!!!!!!!!<br> .<br> .<br> .<br> .<br> .<br> .<br> .<br> .<br> . 0+0=?
aalyn [17]

Answer:  0?

Step-by-step explanation:

6 0
3 years ago
find an equation of the line passing through the point (-4,-6) that is parellel to the line y=-2/9x-1
ryzh [129]

<em><u>The equation of the line passing through the point (-4,-6) in slope intercept form is:</u></em>

y = \frac{-2}{9}x -\frac{62}{9}

<em><u>Solution:</u></em>

Given that we have to write the equation of the line passing through the point (-4,-6) that is parallel to the line y=-2/9x-1

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ---------- eqn 1

Where, "m" is the slope of line and "c" is the y intercept

<em><u>Given equation of line is:</u></em>

y = \frac{-2x}{9} -1

<em><u>On comparing the above equation with eqn 1,</u></em>

m = \frac{-2}{9}

We know that slopes of parallel lines are equal

Thus slope of line parallel to given line is also \frac{-2}{9}

Now find the equation of line with slope \frac{-2}{9} and passing through (-4, -6)

\text{Substitute } m = \frac{-2}{9} \text{ and } (x, y) = (-4, -6) \text{ in eqn 1}\\\\-6=\frac{-2}{9} \times -4+c\\\\-6 = \frac{8}{9}+c\\\\-6 = \frac{8+9c}{9}\\\\-54 = 8+9c\\\\9c = -62\\\\c = \frac{-62}{9}

\text{Substitute } m = \frac{-2}{9} \text{ and } c = \frac{-62}{9} \text{ in eqn 1}\\\\y = \frac{-2}{9}x -\frac{62}{9}

Thus the equation of line is found

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3 years ago
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BlackZzzverrR [31]

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kramer

Answer:

49.2 feet

Step-by-step explanation:

x=73/Tan56=49.2391=49.2

5 0
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