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ANEK [815]
3 years ago
15

a 5m long ladder is placed against a wall with its foot 1.8m from the wall.find how far up the wall the ladder reaches?

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0
Since you have the hypotenuse (5) and the adjacent side (1.8) all you have to do is find out what squared times 1.8 squared equals 5 squared. the formula for this is a^2 + b^2 = c^2

Now to figure this out you can do 5^2 which equals 25. 
Then you do 1.8^2 which equals 3.24. then you subtract the two and get 21.76.
if you find the square root of 21.76 you will get 4.6647.
4.6647 is the distance of how far up the wall the ladder reaches.
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This problem uses the teengamb data set in the faraway package. Fit a model with gamble as the response and the other variables
hichkok12 [17]

Answer:

A. 95% confidence interval of gamble amount is (18.78277, 37.70227)

B. The 95% confidence interval of gamble amount is (42.23237, 100.3835)

C. 95% confidence interval of sqrt(gamble) is (3.180676, 4.918371)

D. The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

Step-by-step explanation:

to)

We will see a code with which it can be predicted that an average man with income and verbal score maintains an appropriate 95% CI.

attach (teengamb)

model = lm (bet ~ sex + status + income + verbal)

newdata = data.frame (sex = 0, state = mean (state), income = mean (income), verbal = mean (verbal))

predict (model, new data, interval = "predict")

lwr upr setting

28.24252 -18.51536 75.00039

we can deduce that an average man, with income and verbal score can play 28.24252 times

using the following formula you can obtain the confidence interval for the bet amount of 95%

predict (model, new data, range = "confidence")

lwr upr setting

28.24252 18.78277 37.70227

as a result, the confidence interval of 95% of the bet amount is (18.78277, 37.70227)

b)

Run the following command to predict a man with maximum values ​​for status, income, and verbal score.

newdata1 = data.frame (sex = 0, state = max (state), income = max (income), verbal = max (verbal))

predict (model, new data1, interval = "confidence")

lwr upr setting

71.30794 42.23237 100.3835

we can deduce that a man with the maximum state, income and verbal punctuation is going to bet 71.30794

The 95% confidence interval of the bet amount is (42.23237, 100.3835)

it is observed that the confidence interval is wider for a man in maximum state than for an average man, it is an expected data because the bet value will be higher than the person with maximum state that the average what you carried s that simultaneously The, the standard error and the width of the confidence interval is wider for maximum data values.

(C)

Run the following code for the new model and predict the answer.

model1 = lm (sqrt (bet) ~ sex + status + income + verbal)

we replace:

predict (model1, new data, range = "confidence")

lwr upr setting

4,049523 3,180676 4.918371

The predicted sqrt (bet) is 4.049523. which is equal to the bet amount is 16.39864.

The 95% confidence interval of sqrt (wager) is (3.180676, 4.918371)

(d)

We will see the code to predict women with status = 20, income = 1, verbal = 10.

newdata2 = data.frame (sex = 1, state = 20, income = 1, verbal = 10)

predict (model1, new data2, interval = "confidence")

lwr upr setting

-2.08648 -4.445937 0.272978

The predicted bet value for a woman with status = 20, income = 1, verbal = 10, which shows a negative result and does not fit with the data, so it is inferred that model (c) does not fit with this information

4 0
3 years ago
What is the slope of the line that contains the points (-3, -2) and (4, -2)?
schepotkina [342]
You have to use the formule: y2-y1/x2-x1
-2-(-2)/4-(-3)=0/7
6 0
3 years ago
Read 2 more answers
Which pair of equations represents two perpendicular lines? <br>answers shown in picture. ​
kolezko [41]

Answer:

y =1/2x+6

y = -2x+2

Step-by-step explanation:

Perpendicular line have slopes that multiply to -1

The slopes are negative reciprocals

-4*4 = 16  not perpendicular

1/2 * -2 = -1  perpendicular

1/5 *5 = 1  not perpendicular

2/3 * 2/3 = 4/9  not perpendicular

3 0
3 years ago
Kevin is 333 years older than Daniel. Two years ago, Kevin was 444 times as old as Daniel.
tia_tia [17]

Answer: the equations are

k = d + 33

k - 2 = 4(d-2)

Step-by-step explanation:

Let the present age of Kevin be represented by k

Let the present age of Daniel be represented by d

Kevin is 33 years older than Daniel. This means that the expression for their current age is

k = d + 33

Two years ago, Kevin was 4 times as old as Daniel. This means that 2 will be subtracted from their present ages to depict two years ago. Therefore, Two years ago for Daniel will be d-2

Two years ago for Kevin will be k - 2

Remember that Kevin was 4 times as old as Daniel two years ago, it becomes

k - 2 = 4(d-2)

5 0
3 years ago
Read 2 more answers
7x^2 +2× when x = 3?
borishaifa [10]

Answer:

7(3^2) + 2(3).

That equals to 7(9) + 2(3).

That equals to 63 + 6.

That finally equals to 69.

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
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