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Goryan [66]
3 years ago
8

Which of the following answers describes the most direct consequence of tropomyosin binding to F-actin in muscle cells?

Biology
1 answer:
svetlana [45]3 years ago
7 0

Answer:

\rMyosin binding to F-actin is blocked

Explanation:

Tropomyosin is a protein involved in skeletal muscle contraction and that wraps around actin and prevents myosin from grabbing it. This prevents muscle contractions until the proper signal arrives. When the nervous system tells the muscle cell to contract, calcium is released.

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Finding common metabolic pathways, such as the tricarboxylic acid (Krebs) cycle, in both prokaryotic and eukaryotic organisms is
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Answer:
             There are difference in the TCA cycle of both prokaryotes and eukaryotes. In prokaryotes mitochondria is absent of TCA occurs in the cytosol. In eukaryotes it occurs in the mitochondria.
<span>In this pathway, an NADP-dependent enzyme </span><span>catalyzes the dehydrogenation of </span><span>D-threo-isocitrate</span><span> to </span>2-oxoglutarate<span>, while eukaryotes employ an NAD+-dependent enzyme</span><span>. Another difference is that while in most eukaryotes the conversion of </span><span>(S)-malate</span><span> to </span>oxaloacetate<span> is catalyzed only by an NAD-dependent enzyme, p</span><span>rokaryotes that employ this variation of the TCA cycle possess an alternative quinone-dependent enzyme.</span>
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2 years ago
Proteins are made from amino acids. An amino acid has three parts that are joined to a central carbon atom. Identify the three p
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amine group , alkyl group and carboxyl group

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A hidden population has been discovered in Turkey. Researchers have calculated that 22% of the population have Uner Tan Syndrome
Rainbow [258]

Answer:

Thus, 50% of the population are are heterozygous carriers for this condition

Explanation:

Researchers have calculated that 22% of the population have Uner Tan Syndrome. This condition follows the recessive mode of inheritance.

22% have the condition = q² (genotypic frequency uu) = 22/100 = 0.22

using the formular p + q = 1, since q² = 0.22, q = √0.22 = 0.4690

Thus p = 1-q where  is 0.4690 = 1-0.4690

  p = 0.5310

Then p² = 0.5310² = 0.2820 = 28% (genotypic frequency of homozygous normal)

using the formula p² + 2pq + q² where 2pq is the genotypic frequency of the heterozygous carriers. Thus, we have

2 x 0.5310 x 0.4690 = 0.498 = 50%

Thus, 50% of the population are are heterozygous carriers for this condition

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Explanation:

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if a dominant flower is red and a recessive is white, what would the heterozygote be if the flower demonstrates incomplete domin
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