there will be one solution because the lines intersect at exactly one set of points.
(0,6)(6,3)
slope(m) = (3-6) / (6-0) = -3/6 = -1/2
y = mx + b
6 = -1/2(0) + b
6 = b
y = -1/2x + 6
(0,0)(6,6)
slope(m) = (6-0) / (6-0) = 6/6 = 1
y = mx + b
6 = 1(6) + b
6 = 6 + b
6 - 6 = b
0 = b
y = x + 0
x = -1/2x + 6
1/2x + x = 6
1/2x + 2/2x = 6
3/2x = 6
x = 6/(3/2)
x = 6 * 2/3
x = 12/3 = 4
<span>solution is : (4,4)</span>
D. x+ 40 = 150 this is the answer
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
Answer:
Option C.
Step-by-step explanation:
Given information:
Sample size = 150
Number of Opinions = 3 (Yes, No, No Opinion)
Yes = 40
No = 60
No opinion = 50
We need to find the expected frequency for each group.
Expected frequency for each group is the quotient of sample size and number of opinions.



Therefore, the correct option is C.
Answer: 7x + 9y >_ (more or equal) 314
X + Y <_ ( less or equal) 35
Step-by-step explanation: