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3 years ago

Find the area of the circle. Round your answer to the nearest hundredth. Use. 3.14 or 22/7 for pi. 10 inch

Mathematics

1 answer:

yKpoI14uk [10]3 years ago

7 0

Answer:

=314in²

Step-by-step explanation:

$r=10in$

$s=\pir^2=\pi:100$

$Assuming\ \pi=3.14:5=3.10\bullet100$
$=314{\rm in}^2$

<em>I hope this helps you</em>

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Stoplight a changes color every 30 seconds and stoplight b changes every 40 seconds. after how many seconds will the stoplights

andrey2020 [161]

Answer:

After 120 seconds

Step-by-step explanation:

Here, we want to know the number of seconds after which both spotlights will change colors at the same time again.

Basically, what we want to do here is to

calculate the value with which 30 and 40 have the same multiples or we want to

calculate the lowest common multiple of 30 and 40

The multiples of 30 are 30,60,90,120 etc

The multiples of 40 are 40,80,120 etc

We can see that the lowest common multiple of both is 120

So therefore the spotlights will change colors at the same time after 120 seconds

6 0

3 years ago

All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,

Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side $l$ , its diagonal would be $l\sqrt{2}$ , and its area $l^2$

If the big square has a area of 900, this implies that its side is $\sqrt{900}$ , so the two diagonal of squares 2 and 4 added together would be $\sqrt{900}$ , therefore one diagonal wold be $\frac{\sqrt{900}}{2}$ . and its side $\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}$ . The area (of one square) is $(\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}$

finally the two areas combined (squares 2 and 4) would be 225

6 0

3 years ago

Suppose an aquarium has a length of 4 feet, a width of 2 feet, and is filled with water to a depth of 9 feet. A reef is placed i

BigorU [14]

Answer:

$24ft^3$

Step-by-step explanation:

The information that we kow about the shape of the aquarium:

length:

$l=4ft$

width:

$w=2ft$

when the reef is submerged, the water level rises 3 feet. The volume that those 3 ft represent in the aquarium will be the volume of the reef.

Thus, we calculate the volume of water "addition" with the same length and width as the aquarium but with a deep of 3 feet (thi is because the reef caused the water to rise 3 feet), and this is the volume of the reef that was added to the aquarium:

$V=4ft*2ft*3ft\\V=24ft^3$