Answer:
189.8 m
Step-by-step explanation:
See the diagram attached.
Now, the plane is at B and the two ships are at C and at D.
So, angle of depression of C from B is ∠ OBC = ∠ ACB = 35°
Again, the angle of depression of D from B is ∠ OBD = ∠ ADB = 25° ,
Now, from the right triangle Δ ACB,
⇒ m.
Similarly, from the right triangle Δ ADB,
⇒ m.
Hence, the distance between the ships = CD = AD - AC = 568.3 - 378.5 = 189.8 m (Approx.) (Answer)
