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jek_recluse [69]

3 years ago

10

Find the probability that when a couple has five children at least one of them is a boy

1 answer:

denis23 [38]3 years ago

4 0

Answer:

it's a 50/50 chance per child because a boy requires one X chromosome and one y chromosome

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What two numbers can you multiply to get 84?

svet-max [94.6K]

84 ÷ 2 = 42

Check it to make sure.

2 × 42 = 84

42 and 2 can be multiplied to get 84.

7 0

3 years ago

A jetliner cruises 12 miles for every 60 gallons of fuel it uses . If it used 1,200 gallons of fuel how many miles did it cruise

Romashka [77]

60g/12miles = 5g/mile
So, 1200g / 5g = 240 miles

3 0

3 years ago

The table below shows the amounts of cherry juice and soda used in each container of cherry soda. The ratio of cherry juice to s

lana66690 [7]

It would be 4!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

8 0

3 years ago

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A bicycle and a tricycle manufacturer makes bikes and trikes with the same size of wheels. They received a shipment of 100 wheel

natima [27]

2 trikes (6 wheels) and 47 bikes (94 wheels)
or
4 trikes (12 wheels) and 44 bikes (88 wheels)
or
6 trikes (18 wheels) and 41 bikes (82 wheels)
or
8 trikes (24 wheels) and 38 bikes (76 wheels)
or
10 trikes (30 wheels) and 35 bikes (70 wheels)

As long as you start our with an even number of trikes, you'll find a way to use up all the tires with no remainders.

4 0

3 years ago

Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

$(x-2)\\ (x-3)\\ (x-5)$

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

$x=2\\ x=3\\ x=5$

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

$(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0$

therefore

the answer Part b) is

the cubic polynomial function is equal to

$x^{3}-10x^{2} +31x-30=0$

7 0

2 years ago

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