Answer:
perimeter of a regular hexagon=6×side length
side length in question is 'k'
perimeter=6×k=6k
Answer: 120 ways
Step-by-step explanation:
Let's label the routes a, b, c, d, and e. The goal is to come up with as many unique permutations as possible.
1 route: a=1. one factorial (1!) =1*1=1
2 routes: ab, ba=2. 2!=1*2=2
3 routes: abc, acb, bac, bca, cab, cba=6. 3!=1*2*3=6
4 routes: 4!=1*2*3*4=24
5 routes: 5!=1*2*3*4*5=120 ways
Answer:
A,B,C
Step-by-step explanation:
in these quadrilaterals, the diagonals bisect each other paralellogram, rectangle, rhombus, square
in these quadrilaterals, the diagonals are congruent rectangle, square, isosceles trapezoid
in these quadrilaterals, each of the diagonals bisects a pair of opposite angles rhombus, square
Answer:
c = 2
Step-by-step explanation:
(x, y) = (-1, 3)
3 = c - (-1)^2 - 2(-1)
3 = c - 1 + 2
3 = c + 1
2 = c
