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Sphinxa [80]
3 years ago
9

Difficult pre calculus stuff.

Mathematics
1 answer:
leva [86]3 years ago
7 0

When we divide complex numbers we divide their magnitudes and subtract their angles, so this isn't all that difficult:

\dfrac{10(\cos 45^\circ + i \sin 45^\circ)}{5 (\cos 15^\circ + i \sin 15^\circ)} = \dfrac{10}{5} (\cos(45^\circ - 15^\circ) + i \sin(45^\circ - 15^\circ))

= 2(\cos 30^\circ + i \sin 30^\circ)

Answer: 2(\cos 30^\circ + i \sin 30^\circ)

That's probably what's called simplified polar form until you get to Euler's Formula.   Since it's 30 degrees we can get a nice rectangular form:

2(\cos 30^\circ + i \sin 30^\circ) = 2\left( \dfrac{\sqrt{3}}{2} + i \dfrac 1 2 \right) = \sqrt{3} + i


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