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3 years ago

Can someone please help me with these 2 problems. With work please & thank u

Mathematics

1 answer:

Triss [41]3 years ago

4 0

Answer:

I'm not good with the type of math on 3, so I'm going to answer 4. (P.S I don't know the question you're asking, so I'm going to assume you want to know the area and perimeter of the shapes.

Step-by-step explanation:

To solve number 4 I added the width of the 2 triangles to give me the width of the rectangle, so then 2 times 9 is 18. Then for the triangles. The formula for triangles is base times height divided by 2. So we add the areas of all shapes and we get: 18+6+24=48m. So the area for number 4 is 48 meters.

(hope this was your question)

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How do I solve fro r and q?<br><br> 9r+q=13<br> 3r+2q=-4

olga55 [171]

One way to solve the system of equations would be to solve for q (in terms of r) in the first equation to get:
9r + q = 13
q = 13 - 9r

Then, take the value for q you just found and insert it into the second equation:
3r + 2(13-9r) = -4

Then simplify and solve:
3r + 26 - 18r = -4
-15r = -30
r = 2

Now that you have the value for r, plug it into either of the original equations and solve for q:
9r + q = 13
9(2) + q =13
18 + q = 13
q = -5

r = 2; q = -5

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Answer:

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Step-by-step explanation:

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