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Please mark me as brainleist
<u>the correct question is</u>
The denarius was a unit of currency in ancient rome. Suppose it costs the roman government 10 denarii per day to support 4 legionaries and 4 archers. It only costs 5 denarii per day to support 2 legionaries and 2 archers. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Let
x-------> the cost to support a legionary per day
y-------> the cost to support an archer per day
we know that
4x+4y=10 ---------> equation 1
2x+2y=5 ---------> equation 2
If you multiply equation 1 by 2
2*(2x+2y)=2*5-----------> 4x+4y=10
so
equation 1 and equation 2 are the same
The system has infinite solutions-------> Is a consistent dependent system
therefore
<u>the answer is</u>
We cannot solve for a unique cost for each soldier, because there are infinite solutions.
<span>2(3z-2)+8=34
6z - 4 + 8 = 34
6z + 4 = 34
6z = 34 -4
6z = 30
z =30/6
z = 5
answer </span><span>D. z=5</span>
Answer:
Because this question was posted 4 days ago I'm assuming that you Oliver don't need any help anymore,... BUT,... with the amount of info given it is not possible to answer the question for example,...
- They could sell: 4 adult tickets costing $15 each and 2 student ones cost $1 dollar each,...
All of that adding up to $64
- Or they could sell: 4 adult tickets costing $10 each and 2 student ones cost $11 dollar each,...
All of that adding up to $64
- OR still (you're probably annoyed by now,... sorry) they could sell: 4 adult tickets costing $6 each and 2 student ones cost $19 dollar each,...
AND All of that adding up to $62
You get the point,... Hope that helped and see you in life,... (well actually because we're probably never going to meet each other in real life then no I probably won't see you in life,... but, I mean, you get the idea) Chow!
Answer:
s2 = 19 a=19 u1= 19√2 (26.87) u2= 19√2 (26.87)
Step-by-step explanation:
s2 - subtrace s1 from h to get 19
a - use the geometric mean of s1 and s2 (squre root of 19 times 19)
u1 and u2 - pythagorean thm
