All categories

2 years ago

Pls help :Find the missing side or angle. Round to the nearest tenth.

Mathematics

2 answers:

Nitella [24]2 years ago

7 0

Answer:

C° = 71.6056

Step-by-step explanation:

Law of Cosines: c² = a² + b² - 2abcosC°

Step 1: Plug in known variables

29² = 30² + 15² - 2(30)(15)cosC°

Step 2: Evaluate

841 = 900 + 225 - 900cosC°

-59 = 225 - 900cosC°

-284 = -900cosC°

71/225 = cosC°

cos⁻¹(71/225) = C°

C° = 71.6056

And we have our answer!

ruslelena [56]2 years ago

3 0

Answer:

79.0°

Step-by-step explanation:

The Law of Cosines is used for this purpose. It tells you ...

a² = b² +c² -2bc·cos(A)

Solving for A gives ...

cos(A) = (b² +c² -a²)/(2bc) = (15² +29²-30²)/(2(15)(29)) = 166/870

Using the inverse cosine function, we find the angle to be ...

A = arccos(166/870) ≈ 79.00026°

A ≈ 79.0°

You might be interested in

Question in screenshot.

Kitty [74]

Your answer is b. hope this helps :)

4 0

3 years ago

Write a positive or negative integer that represents the situation. You earn $15 raking leaves. The integer represents the situa

beks73 [17]

Answer:

+$15

Step-by-step explanation:

Amount earned for raking leaves = $15

Representing the amount earned above. As a positive or negative integer will depend on what the money is used for or stands for.

Amount earned for working adds to one's wealth while expenses will be represented as negative as it decreases the amout one has ;

Hence, integer ; +$15

8 0

2 years ago

4r+9r-11r+7r= Simplify Combine like terms

Veseljchak [2.6K]

Answer:

Step-by-step explanation:

4r+9r-11r+7r

Combine like terms

13r -11r+7r

2r+7r

3 0

2 years ago

Read 2 more answers

6,10,14 ... Find the 30th term.

andriy [413]

Answer:

Step-by-step explanation:

$a_n=a_1+d(n-1)\\\\\\10-6=4 \ \ and\ \ 14-10=4\quad\implies\qquad d=4\\\\a_1=6\\\\\\a_{30}=6+4(30-1)=122$

7 0

2 years ago

A square matrix A is said to be idempotent iff A2 = A. (i) Show that if A is idempotent, then so is I − A. (ii) Show that if A i

muminat

Answer:

Step-by-step explanation:

Given that A is a square matrix and A is idempotent

$A^2 = A$

Consider I-A

i) $(I-A)^2 = (I-A).(I-A)\\= I^2 -2A.I+A^2\\= I-2A+A\\=I-A$

It follows that I-A is also idempotent

ii) Consider the matrix 2A-I

$(2A-I).(2A-I)=\\4A^2-4AI+I^2\\= 4A-4A+I\\=I$

So it follows that 2A-I matrix is its own inverse.

7 0

3 years ago