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2 years ago

Evaluate t-u/v, when t=-1,u=-3 and v=1/2

Mathematics

1 answer:

mars1129 [50]2 years ago

3 0

Answer:

Step-by-step explanation:

t-u/v

substitute (-1) - (-3)/(1/2)

divide (-1) - (-6)

simplify (-1) + 6

add 5

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Answer:

1. positive

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2 years ago

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A work cell is scheduled to build 120 digital light processor (dlp) assemblies each week. these assemblies are later installed i

timurjin [86]

Work cell produces 120 digital light processors in a week. We want to find the time spent on each processor in minutes. So for this first we will find the total time spent on 120 processors in a week.

Number of productive hours in a day = 7.5
Working days per week = 6
So, number of productive hours per week = 6 x 7.5 = 45 hours

1 hour = 60 minute

So,number of productive minutes per week = 45 x 60 = 2700 minutes

120 processors are produced in time = 2700 minutes

1 processor is produced in time = 2700/120 minutes = 22.5 minutes

So, it takes 22.5 minutes to produce one digital light processor

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3 years ago

PLEASE HELP PLATO ALGEBRA 2 Select ALL the correct answers.

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Answer:

I think B and C

Step-by-step explanation:

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3 years ago

Use the hundredths grid to answer the question.

professor190 [17]

The question is an illustration of multiplication model.

The multiplication model is: $\mathbf{0.90 \times 0.10 =0.09}$

From the figure, the shaded portions are:

$\mathbf{Green = \frac{90}{100}}$

$\mathbf{Orange = \frac{10}{100}}$

So, the multiplication model represents:

$\mathbf{Model =Green \times Orange}$

This gives

$\mathbf{Model =\frac{90}{100} \times \frac{10}{100}}$

Express as decimal

$\mathbf{Model =0.90 \times 0.10}$

$\mathbf{Model =0.09}$

Hence, the multiplication model is:

$\mathbf{0.90 \times 0.10 =0.09}$

Read more about multiplication models at:

brainly.com/question/1928793

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2 years ago

Joe and Maxine are playing a game where they flip a fair coin four times and try to predict the outcomes. Joe thinks that the pr

timofeeve [1]

Answer: Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.

Step-by-step explanation:

First creating a sample space :

HHHH, HHHT, TTHT, HTTH, THHH, TTTT, TTTH, TTHH, HTHH, HTTT, HHTT, THTH, HHTH, THTT, HTHT, THHT

A fair coin (H - HEAD, T - TAIL)

Probability = (required outcome / possible outcome)

Probability getting exactly two heads in first four flips:

= 6/16 = 3/8

Probability of getting head on both the first and second flips :

= 4/16 = 1/4

Therefore Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.

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3 years ago

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