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Volgvan
3 years ago
7

Which statement best explains ?

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0
A is the correct answer. Hope this helps. I need brainliest so if you can I really appreciate it!
You might be interested in
Joanne has a cell phone plan that charges a flat rate of $97 and $0.10 for every text she sends. Her goal is to spend less than
Alik [6]
I’m pretty sure the answer would be A,because if her bill is $97 and it’s $0.10 every txt she sends then and she wants to spend less then $113 then if you take $113 and subtract it by 97 it gives you 16 then if you divided 16/ 0.10 then it gives you 160 so she is sending atleast 160 txt.
6 0
3 years ago
There is a bag with only red marbles and blue marbles.
mote1985 [20]

Answer:

red marbles

Step-by-step explanation:

Since the formula is;

Probability = number of required outcome

_______________________

number of possible outcome

3/8. = x/56

8x. = 168

x. 21 ( number of blue marbles)

Therefore if the total marbles = 56 and 21 of the marbles are blue then to get the red marbles

= 56 - 21

= 35

3 0
3 years ago
Please help me ill put the question up for a lot of point, and i will mark as brainliest!!!
sattari [20]

Step-by-step explanation:

(2x³y^-4)^-2 = 1/(4x⁶y^‐8) = y⁸/(4x⁶)

1/(8x⁵y^-7) = y⁷/(8x⁵)

4x^-9y⁴ = 4y⁴/x⁹

so, the whole expression is then

y⁸/(4x⁶) × y⁷/(8x⁵) × 4y⁴/x⁹

4y¹⁹/(32x²⁰) = y¹⁹/(8x²⁰)

so, D is the correct answer.

6 0
3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
75,981 rounded to the nearest ten-thousand
Zinaida [17]

Answer:

80,000

Step-by-step explanation:

7 is the tean thousand

Add 1 because 5 is a big amount.

5 0
2 years ago
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