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SCORPION-xisa [38]

3 years ago

14

The table below shows data from a survey about the amount of time high school students spent reading and the amount of time spen

t watching videos each week (without reading):
Reading Video
4 4
4 5
5 6
5 8
5 9
6 10
7 11
8 12
8 14
9 25

Which response best describes outliers in these data sets?
Neither data set has suspected outliers.
The range of data is too small to identify outliers.
Video has a suspected outlier in the 25-hour value.
The 25-hour value for video does not pass the outlier test of 1.5 ⋅ (IQR) + Q3.

1 answer:

ira [324]3 years ago

5 0

Video has a suspected outlier in the 25 hr value

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Stephanie had a total of 80 pieces of $ 2 and $ 10 notes. After spending 2/5 of her $ 2 notes and 8 pieces of her $ 10 notes, sh

Ghella [55]

Answer:

$440

Step-by-step explanation:

notes $2 - n

notes $10 - m

n + m = 80 ----------> m = 80 - n

1 - 2/5 = 3/5

$\frac{3}{5} * n = m - 8$

$\frac{3}{5} * n = 80 - n - 8 \\\\\frac{3}{5} * n + n = 72\\\\\frac{8}{5} * n = 72\\n = 45 \\m = 35\\$

45 * $2 + 35 * $10 = 90 + 350 = $440

3 0

3 years ago

1. How much is 50% of 10 liters of milk?

Firlakuza [10]

1. 5 liters of milk
2. 1,000 kilometers
3. 12 hours
4. Divide the number by two or multiply by 0.5
5. 200 kilometers
6. 1 liter of milk
7. 2.4 hours or 2 hours and 15 min.
8. Multiply the number by 0.1

7 0

3 years ago

Read 2 more answers

Solve T=C(5+ AB) for B.

Vaselesa [24]

Answer:

$b = \frac{t - 5}{a}$

Step-by-step explanation:

$t = c(5 + ab)$

Simplify:

$t = 5c + abc$

Move 5c to the other side:

$t - 5c = abc$

Divide bother sides with AC:

$\frac{t - 5c}{ac} = \frac{abc}{ac}$

Simplify:

$\frac{t - 5}{a} = b$

If this answer helped you, give this answer a heart, rate it and if you could then please mark it brainliest. Thanks!

8 0

1 year ago

The quadrilateral WXYZ has vertices W(3,-5) X(1,-3) Y(-1,-5) and Z(1,-7)

dmitriy555 [2]

The preimage WXYZ is to undergo a rotation of 90° in the clockwise direction.
A 90° clockwise rotation leads to the following change in the coordinates;
(x,y) -> after rotation (y,-x)
this rule applies for all the vertices in the preimage
W - (3,-5) --> W' (-5,-3)
X - (1,-3) ---> X' (-3,-1)
Y - (-1,-5)---> Y' (-5,1)
Z - (1,-7) ---> Z' (-7,-1)
therefore the new coordinates are W' (-5,-3), X' (-3,-1), Y' (-5,1) and Z' (-7,-1)

5 0

3 years ago

The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated

cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

<em>Let </em> $p_1$ <em> = proportion of cockroaches that died on glass surface.</em>

<em /> $p_2$ <em> = proportion of cockroaches that died on plasterboard surface.</em>

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq$ 0 {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here <u>Two-sample z proportion</u> <u>statistics</u>;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of cockroaches that died on glass surface = $\frac{18}{36}$ = 0.50

$\hat p_2$ = sample proportion of cockroaches that died on plasterboard surface = $\frac{25}{36}$ = 0.694

$n_1$ = sample of cockroaches on glass surface = 36

$n_2$ = sample of cockroaches on plasterboard surface = 36

So, <u><em>test statistics</em></u> = $\frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36} } }$

= -1.712

The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0

3 years ago