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tia_tia [17]
3 years ago
11

the sum of three positive integers is 20 if the smaller 2 integers differ by 5 ,what is the smallest possible value of the large

r integer?
Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

Step-by-step explanation:

1. Yeet it

2. Delete it

3. Comit self deletus

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The question is attached at the bottom. PLEASE HELP with detailed explanation!!!
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The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim
Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

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Hope this helped.

3 0
3 years ago
If angle 1 = 6n + 1 and angle 4 = 4n + 19, what is the angle 2?
kobusy [5.1K]
Angles 1 and 4 are alternate angles and thus have the same measurement. You will set their equations equal to each other and solve for the variable. 

6n + 1 = 4n + 19

Subtract 1 and 4n from both sides to get variables on one side and constants on the other. 

6n - 4n = 19 - 1

Combine like terms and solve for n.

2n = 18
n = 18 / 2
n = 9

Angles 1 and 2 are congruent as labeled in the graph. 

So angle 2 is also 6n + 1

Plug in for 9 for n

6(9) + 1
54 + 1
55

Option C is your answer. 


7 0
3 years ago
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