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dedylja [7]
2 years ago
9

Can you help me im not that good at math and its a clear photo y =___x^2+__x+______

Mathematics
1 answer:
geniusboy [140]2 years ago
3 0
  • Vertex/General Form: y = a(x - h)^2 + k, with (h,k) as the vertex
  • (x + y)^2 = x^2 + 2xy + y^2
  • Standard Form: y = ax^2 + bx + c

So before I put the equation into standard form, I'm first going to be putting it into vertex form. Since the vertex appears to be (-1,7), plug that into the vertex form formula:

y=a(x-(-1))^2+7\\y=a(x+1)^2+7

Next, we need to solve for a. Looking at this graph, another point that is in this line is the y-intercept (0,5). Plug (0,5) into the x and y placeholders and solve for a as such:

5=a(0+1)^2+7\\5=a(1)^2+7\\5=a+7\\-2=a

Now we know that <u>our vertex form equation is y = -2(x + 1)^2 + 7.</u>

However, we need to convert this into standard form still, and we can do it as such:

Firstly, solve the exponent: y = -2(x^2+2x+1) + 7

Next, foil -2(x^2+2x+1): y = -2x^2-4x-2+7

Next, combine like terms and <u>your final answer will be: y = -2x^2-4x+5</u>

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forsale [732]

Answer:

The first five terms are;

-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

a_1=-3,, a_2=-7 and a_n=a_{n-2}-2a_{n-1}.

When n=3, we obtain;

a_3=a_{3-2}-2a_{3-1}.

\implies a_3=a_{1}-2a_{2}.

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\implies a_3=11.

When n=4

\implies a_4=a_{2}-2a_{3}.

\implies a_4=-7-2(11)=-29.

When n=5

\implies a_5=a_{3}-2a_{4}.

\implies a_4=11-2(-29)=69.

Therefore the first five terms are;

-3,-7,11,-29,69

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