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4 years ago

Which are these are polygons

Mathematics

1 answer:

oee [108]4 years ago

3 0

<h3>3 Answers: B, C, F</h3>

Each of these are closed figures formed by straight line segments. Think of fencing in an area (not necessarily a rectangle) using various straight fence sections. The length of each section does not have to be the same.

Side notes:

Choice A is not a polygon because the figure is not closed.
Choice D is not a polygon because it is not composed of line segments only. Choice D is an ellipse instead.
Choice E is not a polygon due to the curved portion.

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What is the maximum number of times two planes can intersect? What is the minimum number of times they can intersect?

nordsb [41]

The minimum number of times two planes can intersect is zero, because if the planes are parallel to each other, they will never intersect. we can take the example of floor and roof, both are parallel to each other and no intersection. If the two planes are in same plane the maximum number of times they can intersect is infinite for example if we consider a line we can intersect at infinite points.

8 0

3 years ago

Please help please please

Keith_Richards [23]

Answer:

Step-by-step explanation:

Givens:

m: 2/3 m and 5/6 m

rational numbers: -1 1/6 and - 1 1/3

Combine the givens

2/3 m + 5/6 m Change 2/3 m to something over 6

2/3m = 2*2 m / 3*2

2/3 m = 4 m /6

4m/6 + 5m / 6 = 9 m/6 = 1 1/2 m

Result: B and D are both incorrect

Now work on the rationals. Change the -1 1/3 into -1 something / 6

Change 1/3 into something over 6

-1 1/6 - 1 1/3 change - 1 1/3 = -1 2*1 /3*2

-1 1/6 - 1 2/6

-1 1/6 - 1 2/6 = 2 (1 + 2)/6

-1 1/2

Answer: C

4 0

3 years ago

Read 2 more answers

Specifications call for the wall thickness of two-liter polycarbonate bottles to average 4.0 mils. A quality control engineer sa

bija089 [108]

Answer:

The null hypothesis μ=4.0 could not be rejected.

Step-by-step explanation:

In this problem we have to perform a hypothesis test of the mean, with s.d. of the population unknown.

The sample is: [3.999, 4.037, 4.116, 4.063, 3.969, 3.955, 4.091]

This sample has a mean of 4.033 and a standard deviation of 0.061.

The null and alternative hypothesis are:

$H_0: \mu = 4.0\\\\H_1: \mu \neq 4.0$

We assume a significance level of 0.05.

The test statistic for this test is:

$t=\frac{M-\mu}{\sigma}=\frac{4.033-4.0}{0.061}=0.536$

We have a sample size n=7, so the degrees of freedom are 7-1=6.

For a two-tailed test, t=0.536 and df=6, the P-value can be look up in a t-table.

The P-value is 0.61. Is greater than the significance level, so the effect is not significant and the null hypothesis can't be rejected.

8 0

4 years ago

A distribution has the five-number summary shown below. What is the

Irina-Kira [14]

Answer:

The interquartile range(IQR) is 31.

Step-by-step explanation:

Given:

A distribution has the five-number summary shown below:

24, 36, 42, 57, 65.

Now, to find the interquartile range (IQR).

So, to get the IQR we need to find the quartile 1 and quartile 3:

As, 42 is the median.

Quartile 1 is the average of first half.

24, 36, 42, 57, 65.

Q1 = $\frac{24+36}{2}$

Q1 = $\frac{60}{2}$

Q1 = $30$

Quartile 3 is the average of last half.

24, 36, 42, 57, 65.

Q3 = $\frac{57+65}{2}$

Q3 = $\frac{122}{2}$

Q3 = $61$

Thus, by putting the formula we get IQR:

IQR = Q3 - Q1.

$IQR=61-30$

$IQR=31.$

Therefore, the interquartile range(IQR) is 31.

4 0

3 years ago

How much will 5 pounds cost

Lesechka [4]

Answer:

$6.25

Step-by-step explanation: 10/8=1.25 1.25*5=6.25

8 0

4 years ago