Answer:
a=50 b=20
Step-by-step explanation:
Call A and B the 2 present ages.
Ten years from now, A is twice as old as B -->
(A + 10) = 2(B + 10) (1)
Five years ago, A was 3 times as old as B -->
(A - 5) = 3(B - 5) (2).
Solve the system (1) and (2).
From (2) --> A = 3B - 15 + 5 = 3B - 10.
Replace this value of A into (1) -->
3B - 10 + 10 = 2B + 20 --> B = 20. Then,
A = 3B - 10 = 60 - 10 = 50.
Check
!0 years from now --> A = 60 and B = 30 --> A = 2B .OK
5 years ago --> A = 45 and B = 15 --> A = 3B. OK
Answer:
C.
Step-by-step explanation:
= ![\sqrt[3]{8}^{x}\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%5E%7Bx%7D%5C%5C)
= Since ![\sqrt[3]{} = ^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D%20%3D%20%5E%7B1%2F3%7D)
= So, It becomes :
= 
Y=10(3)^3-12(3)
y=270-36
y=234
