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alina1380 [7]
3 years ago
15

Need some help please.... math...

Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

-14/5

Step-by-step explanation:

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Write a cosine function that has a midline of 2, an amplitude of 4 and a period of 4/7
ella [17]

Answer:

y= 4cos(\frac{7\pi }{2}x)+2

Step-by-step explanation:

We know that the transformations of a cosine equation can be shown as:

y=±a(b(x-h))+k

Where 'a' is the amplitude

'b' is the horizontal change (Do 2π/b to find the period)

'h' is the horizontal shift

and 'k' is the vertical shift or midline.

------------------------------------------------------

If the amplitude is 4, we can assume a=4.

Since the period is 4/7, we can solve for the 'b' value by:

2\pi /\frac{4}{7}= \frac{7\pi }{2}

Next, since the midline is 2, we know that a vertical shift of 2 occurred. Thus, the 'k' value is 2.

Writing this equation gives us:

y= 4cos(\frac{7\pi }{2}x)+2

4 0
4 years ago
What is f + 0.3 < 1.7 I need help solving this please can anybody help me I Tryed and I can't get the answer ?? ??? ??
Elena-2011 [213]
F + 0.3 < 1.7

f < 1.7 - 0.3

f < 1.4

hope this helps!!

3 0
4 years ago
Read 2 more answers
!! please help !!
Pavlova-9 [17]

Answer:

B. 5438

Step-by-step explanation:

[(78-65)×626]-2700=5438

5 0
3 years ago
PLZ HELP if you dont know just dont answer i will give brainliest if you answer right
marta [7]

Answer:  The answer for 1. is 216

The answer for 2. is 224

The answer for 3. is 90

The answer for 4. is 40

The answer for 5. should be 80

Step-by-step explanation:

6 0
3 years ago
Is 56 a multiple of 6
Allushta [10]
No, but 54 is a multiple of 6
5 0
3 years ago
Read 2 more answers
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