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3 years ago

Find the product of 8(477- 18).

Mathematics

2 answers:

3241004551 [841]3 years ago

5 0

Answer:

3672

Step-by-step explanation:

According to BODMAS first we will remove the bracket and then we will multiply

477-18=459

459×8=3672

mel-nik [20]3 years ago

4 0

Answer:

3672

Step-by-step explanation:

8(477-18)

477-18=459

8(459)

=3672

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3 years ago

Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

<u>Answer: </u>

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

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Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

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