The value of x in all case is
1. The value of x is 2
2. The value of x is 1
3.The value of x is 57
4.The value of x is 93
<h3>What is complementary and supplementary angle?</h3>
If the sum of two angles is 180 degrees then they are said to be b angles, which form a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.
1. As the given angle is 90 degree i.e., complementary angle.
So,
54+10x+16=90
20=10x
x=2
2. 65x-12=43x+10 (Vertically opposite angle)
22x= 22
x=1
3. 72= x+15 (Vertically opposite angle)
x= 57
4.x+244+23=360 (Complete angle)
x=93
Learn more about complementary and supplementary angle here:
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Answer:
x = 12, sides = 23
Step-by-step explanation:
Since 
is equilateral, all three sides are equal. Therefore:
![\left[\begin{array}{l}y=2x-1\\y=5x-37\\y=x+11\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7Dy%3D2x-1%5C%5Cy%3D5x-37%5C%5Cy%3Dx%2B11%5Cend%7Barray%7D%5Cright%5D)
Substituting y = x + 11:
![\left[\begin{array}{l}x+11=2x-1\\x+11=5x-37\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bl%7Dx%2B11%3D2x-1%5C%5Cx%2B11%3D5x-37%5Cend%7Barray%7D%5Cright%5D)
Solving for x:
Substituting x = 12:
Thus, <em>x</em> = 12 and the length of each side is 23.
Answer:
-√7/4
Step-by-step explanation:
Mathematically;
Sine is the ratio of opposite to hypotenuse
So here, hypotenuse is 4
The opposite is 3
To get the adjacent, we use the Pythagoras’ theorem which states that the square of the hypotenuse is equal the sum of the squares of the two other sides
Let the adjacent be x
4^2 = 3^2 + x^2
x^2 = 16-9
x^2 = 7
x = √7
The cosine is the ratio of the adjacent to the hypotenuse
Since we want to consider quadrant II
Cosine is negative here;
So the answer for Cos will be;
Cos theta = -√7/4
Answer:
7 x 7 = 49
Step-by-step explanation:
hope it helps, please mark as brainliest please
When a point is reflected across the y-axis, the y-coordinate remains the same. The x-coordinate becomes the opposite.
P(-4, 1) ---> P'(4, 1)
Q(-2, -8) ---> Q'(2, -8)
R(8, -1) ---> R'(-8, -1)
