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Nastasia [14]
3 years ago
13

Choose the words or phrases that best complete the sentences.

Mathematics
2 answers:
blsea [12.9K]3 years ago
7 0

Answer: A fifth degree polynomial <u>could </u>have 5 linear factors. But the factors  <u> do not have</u> to be be distinct.

Step-by-step explanation:

  • The fundamental theorem of algebra tells that every non-constant single-variable polynomial with complex coefficients has at least one complex root.
  • Corollary to the fundamental theorem tells that every polynomial of m>0 degree has exactly m zeroes.

Thus by corollary to fundamental theorem of algebra, a fifth degree polynomial must have 5 zeroes . But A fifth degree polynomial could have 5 linear factors if all zeroes are real numbers.

The factors could be distinct or similar.

Thus , The factors do not have to be distinct .




ASHA 777 [7]3 years ago
5 0
1) Could
2) Could, <span>but don't have to be</span>
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3 years ago
What is the value of y in the equation 4x +3 y= 23 when x=2 , x=6
balandron [24]

Answer:

5, -⅓

Step-by-step explanation:

x = 2:

4x + 3y = 23

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8 0
3 years ago
The shuttle bus from your parking lot and your office building operates on a 15 minute schedule. You arrive at the parking lot a
mylen [45]

Answer:

(a) The standard deviation of your waiting time is 4.33 minutes.

(b) The probability that you will have to wait more than 2 standard deviations is 0.4227.

Step-by-step explanation:

Let <em>X</em> = the waiting time for the bus at the parking lot.

The random variable <em>X</em> is uniformly distributed with parameters <em>a</em> = 0 to <em>b</em> = 15.

The probability density function of <em>X</em> is given as follows:

f_{X}(x)=\frac{1}{b-a};\ a

(a)

The standard deviation of a Uniformly distributed random variable is given by:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

Compute the standard deviation of the random variable <em>X</em> as follows:

SD=\sqrt{\frac{(b-a)^{2}}{12}}

      =\sqrt{\frac{(15-0)^{2}}{12}}

      =\sqrt{\frac{225}{12}}

      =\sqrt{18.75}\\=4.33

Thus, the standard deviation of your waiting time is 4.33 minutes.

(b)

The value representing 2 standard deviations is:

X=2\times SD=2\times4.33=8.66

Compute the value of P (X > 8.66) as follows:

P(X>8.66)=\int\limits^{10}_{8.66} {\frac{1}{15-0}}\, dx\\

                    =\frac{1}{15}\times \int\limits^{10}_{8.66} {1}\, dx\\

                    =\frac{1}{15}\times |x|^{15}_{8.66}\\

                    =\frac{15-8.66}{15}\\

                    =0.4227

Thus, the probability that you will have to wait more than 2 standard deviations is 0.4227.

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