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agasfer [191]
3 years ago
15

Which expression is equivalent to

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Hey there!

(a^8)^4

= a^(8)(4)

8(4) = 32

= a^32

Answer: a^32

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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A manufacturer produces 950 light bulbs per
Inessa05 [86]

Answer:

b =950d

Step-by-step explanation:

The manufacturer makes 950 bulbs a day. So, you have to multiply the number of days by 950 to get the number of bulbs made. This can be written as an equation:

b = 950d

Hope this helps :)

7 0
3 years ago
A. Change the following fractions to mixed numbers.
qaws [65]

Answer:

A )

1 - 1\frac{4}{7}

2 - 5\frac{3}{5}

3 - 3\frac{1}{5}

4 - 4\frac{1}{4}

5 - 6\frac{3}{4}

B )

1 - \frac{1}{4}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{4}{25}

5 - \frac{5}{8}

C )

1 - 1

2 - \frac{3}{4}

3 - 1

4 - \frac{3}{4}

5 - \frac{7}{9}

D )

1 - \frac{5}{12}

2 - \frac{2}{3}

3 - \frac{1}{3}

4 - \frac{1}{2}

5 - \frac{5}{12}

6 0
3 years ago
PLZ HELP QUICKLY! ON A TIMER! What is the answer in the attached image?
VLD [36.1K]

<em>Answer</em>

<em><u>Given</u></em>

<em>the relative frequency tables in the figure below (Note: the tables are not in the same order as in the problem statement)</em>

<em />

<em><u>Find</u></em>

<em>which table is best suited to answer the question</em>

<em />

<em>A) the percentage of home viewers who prefer to watch horror movies </em>

<em />

<em>B) the percentage of people surveyed who prefer to watch comedy movies at home </em>

<em />

<em>C) the percentage of viewers with a preference for drama who watch at the theater </em>

<em />

<em><u>Solution</u></em>

<em>The figure shows the best choices for answering A, B, and C.</em>

<em />

<em>table 2 is best for A (it is normalized by viewing location)</em>

<em />

<em>table 3 is best for B (it is normalized over the whole sample)</em>

<em />

<em>table 1 is best for C (it is normalized by genre)</em>

8 0
3 years ago
How to find the value of the combination? Show your work! Thansk!
elena-14-01-66 [18.8K]

Answer:

A

Step-by-step explanation:

Using the definition

nC_{r} = \frac{n!}{r!(n-r)!}

where n! = n(n - 1)(n - 2).... × 3 × 2 × 1

Then evaluating numerator and denominator

10C_{3}

= \frac{10!}{3!(7!)}

= \frac{10(9)(8)(7)(6)(5)(4)(3)(2)(1)}{3(2)(1)(7(6)(5)(4)(3)(2)(1)}

Cancel 7(6)(5)(4)(3)(2)(1) on numerator/ denominator, leaving

= \frac{10(9)(8)}{3(2)} = \frac{720}{6} = 120

-------------------------------------------------------------------------------------

6C_{4}

= \frac{6!}{4!(2!)}

= \frac{6(5)(4)(3)(2)(1)}{4(3)(2)(1)(2)}

Cancel 4(3)(2)(1) on numerator/ denominator, leaving

\frac{6(5)}{2} = \frac{30}{2} = 15

-------------------------------------------------------------------------------------

Dividing numerator by denominator gives

\frac{120}{15} = 8 → A

4 0
3 years ago
What is the rule for the given sequence? 3, 8, 23, 68, 203,
EleoNora [17]

Answer: Add the number previously added multiplied by 3;

+3x, where x is the number that was added previously

Step-by-step explanation:

3+5=8. That's the first equation, where 5 is x. Then the next equation, 8+3x=23. 8+15=23. It works for all of the equations, so that's the pattern.

4 0
3 years ago
Read 2 more answers
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