Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer: ![100,000](https://tex.z-dn.net/?f=100%2C000)
Step-by-step explanation:
Given :
![logx - 2 = 3](https://tex.z-dn.net/?f=logx%20-%202%20%3D%203)
add 2 to both sides
![log x = 5](https://tex.z-dn.net/?f=log%20x%20%3D%205)
Therefore :
![x = 10^{5}](https://tex.z-dn.net/?f=x%20%3D%2010%5E%7B5%7D)
![x = 100,000](https://tex.z-dn.net/?f=x%20%3D%20100%2C000)
If there are 8 sides to an octagon, that means that there are 4 equal sides remaining. First, we would subtract 70-12=58. 58 is the total perimeter of the four equal sides remaining. We would then divide 58 by 4 to find the length of each side. You should be able to finish this off. I hope this helped!!!
Answer:
5/6 3/4 2/3
Step-by-step explanation:
Answer: Expected number of tests = 5.013
Step-by-step explanation:
Define random variable X that marks the number of tests required for some certain
group. Observe that if the test is negative for all the people (which has probability 0.95), we make one and only one test. If some of the people is tested positive, we make ten additional tests for every person in that group separately. Hence, the expected number of tests will be for if they are all negative (1 test) and the case of at least one person testing positive (11 tests).
That Is,
E(X) = 1(0.95^10) + 11(1 - (0.95^10))
E(X) = 0.5987 + 4.414 = 5.013