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3 years ago

Will make bianleast

Mathematics

1 answer:

NikAS [45]3 years ago

4 0

Answer:

32 ft

Step-by-step explanation:

The perimeter is basically the area of the outside of a shape. To calculate this, you would add up all the sides together and get the answer.

8 + 8 + 8 + 8=32 or you can just do 8*4 which is also 32

So, the answer is 32

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According to the synthetic division below, which of the following statements are true? Check all that apply. -5(2 6 -8) -10 20 _

Sunny_sXe [5.5K]

***(2x²+6x-8):(x+5)=2x-4
     -2x²-10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
   -4x-8
          4x+20
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
              12 ⇒ A. statement is true.

***When x=-5⇒2*(-5)²+6*(-5)-8=12⇒B. statement is true.

***2x²+6x-8 can also be written as (x+5)*(2x-4)+12 so (x+5) is a factor of 2x²+6x-8⇒C. statement is true.

***When x=5⇒2*5²+6*5-8=72 is not 12⇒D. statement is not true

***(2x²+6x-8):(x+5)=2x+16
     -2x²+10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
        16x-8
             -16x+80
      ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
                     72⇒F. statement is not true

***E. statement is not true.

8 0

3 years ago

Read 2 more answers

Una carretera recta tiene un ángulo de elevación de 3 grados respecto al plano horizontal. ¿Qué distancia hay que recorrer para

geniusboy [140]

Answer:

572.4 m

Step-by-step explanation:

Fórmula del ángulo de elevación =

tan θ = Opuesto / Adyacente

θ = 3 °

Opuesto = 30 m

Adyacente =?

Por eso

bronceado 3 = 30 m / x

Multiplicar cruzada

bronceado 3 × x = 30 m

x = 30 m / bronceado 3

x = 572.43410063m

Aproximadamente = 572.4 m

5 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$