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maw [93]
3 years ago
9

How to open a new word proccessing document

Computers and Technology
1 answer:
ladessa [460]3 years ago
8 0
What are you trying to use if it is windows just go to desktop and right click and you will see open new text document or if you go to your task bar (bottom of screen) and search for word you may have word pad which you can also use.
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There are two String variables, s1 and s2, that have already been declared and initialized. Write some code that exchanges their
Ivan

Answer:

//here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare an initialize first string variables

     String st1="hello";

     // declare an initialize first string variables

     String st2="world";

     // create another string variable

    String st3;

    // exchange the value of both string variables

    st3=st1;

    st1=st2;

    st2=st3;

    System.out.println("value of first String after exchange: "+st1);

    System.out.println("value of second String after exchange: "+st2);

   }catch(Exception ex){

       return;}

}

}

Explanation:

declare and initialize two string variables.Create another string variable "st3". first assign value of "st1" to "st3" after then value of "st2" to "st1" and then  assign value of "st3" to "st2". This will exchange the values of both the string.

Output:

value of first String after exchange: world

value of second String after exchange: hello

8 0
3 years ago
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A common use-case for dictionaries is to store word counts. Let's modify our program below to store the count for each unique wo
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Answer:

word_count={}

for i in text.split:

        if i in word_count:

                word_count[i]+=1

         else:

                 word_count[i]=1

print word_count

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Ano ang dalawang paraan sa paggawa ng abono?​
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Answer:

im sorry i dont understand

Explanation:

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Which of the following careers is part of the Printing Technology pathway?
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Textile designer i think

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Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
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