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Harman [31]
3 years ago
12

For the function f(x) = x2 ­ -12, find (f o f­-1)(4)

Mathematics
2 answers:
lara [203]3 years ago
5 0
I hope this helps you

horsena [70]3 years ago
5 0

Answer: f(f^{-1})(4)=4.


Step-by-step explanation:

Given, f(x)=x^{2} -12,

which implies

f^{-1}(x^{2}-12)=x.

We have,

x^{2}-12=4\\\Rightarrow x^{2}=16\\\Rightarrow x=4,-4.

\therefore f^{-1}(4)=4,-4.

f(f^{-1})(4)=f(4)\\\intertext\textup{or}\\f(f^{-1})(4)=f(-4).

Also,

f(4)=f(-4)=4,

\therefore f(f^{-1})(4)=4.

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Factor. (6x+4) <br><br><br> 3(2x+1) <br><br> 3x + 2 <br><br> 2(3x+2) <br><br> 2(x+2)
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Select all of the following ordered pairs that are in the solution set of the inequality shown
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If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
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