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3 years ago

12

Find the length of the shorter leg of a right triangle if the longer leg is 11 feet more than the shorter leg and the hypotenuse

is 11 feet less than twice the shorter leg.

1 answer:

Nikitich [7]3 years ago

3 0

Step-by-step explanation:

of a right triangle if the longer leg is 11 feet more than the shorter leg and the hypotenuse is 11 feet less than twice the shorter leg.

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Answer:

x = y = 15 $\sqrt{2}$

Step-by-step explanation:

Using the sine ratio and the exact value

sin45° = $\frac{\sqrt{2} }{2}$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{30}$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

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x = 15 $\sqrt{2}$

The triangle is isosceles (45- 45- 90) , then 2 legs are congruent, so

y = x = 15 $\sqrt{2}$

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