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Amiraneli [1.4K]
2 years ago
13

What is the solution to the trigonometric inequality 2sin(x)+3>sin^2(x) over the interval 0<=x<=2pi radians?

Mathematics
1 answer:
OlgaM077 [116]2 years ago
6 0

Answer:

Oh gosh, this was very hard, Answer - C on edge 2021

Please thank me

Step-by-step explanation:

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16,80, 400,...<br> Find the 6th term.
jekas [21]

Answer:

Step-by-step explanation:

50,000

I think

5 0
3 years ago
Values for 24/25 ÷ 4/5.
lions [1.4K]
The answer is 1.2 hope this helped ;)
5 0
3 years ago
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Help me plz help me me plz
yan [13]

Answer:

See below.

Step-by-step explanation:

Gale's work is incorrect. The rotation would give him a horizontal line.

The transformations that are required to give  A'B'  as it is on the grid are a translation of 8 units to the right followed by a translation of 2 units down.

The rotation through 90 degrees clockwise and then a translation of 2 units down would give a horizontal line with B' at the same point as on the diagram but the point A' would  be 6 units to the left on the point (-2, -2).

5 0
3 years ago
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(1) Cos AcosecA=cot A​
Mashutka [201]

Answer:

The Basic Identities are :

cosec(A) =  \frac{1}{ \sin(A) }

\tan(A)  =  \frac{ \sin(A) }{ \cos(A) }

\cot(A)  =  \frac{1}{ \tan(A) }  =  \frac{ \cos(A) }{ \sin(A) }

So for this question :

\cos(A)cosec(A) =  \cot(A)

l.s.h =  \cos(A)  \times  \frac{1}{ \sin(A) }

l.s.h =  \frac{ \cos(A) }{ \sin(A) }

l.sh =  \cot(A)  \: (proven)

7 0
4 years ago
Cube numbers between 100 and 400
Alona [7]

Answer with step-by-step explanation:

Let us find the perfect cubes between 1 to 100.

We know that, 1

3

=1,2

3

=8,3

3

=27,4

3

=64 and the rest numbers i.e. 4,5,6,.... have their cubes greater than 100.

So, only these four numbers have their cubes between 1 to 100.

Thus, there are 4 perfect cubes from 1 to 100.

Now, let's find the cubes between −100 to 0

We know, 0

3

=0,(−1)

3

=−1,(−2)

3

=−8,(−3)

3

=−27,(−4)

3

=−64 and the rest numbers have their cubes less than −100

So, only these 5 numbers have their cubes between −100 to 0 and 4 perfect cubes are there from 1 to 100.

Thus, there are 9 perfect cubes from −100 to 100.

plz mark me as brainliest.

5 0
3 years ago
Read 2 more answers
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