10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.
<h3>Which is the required expressions?</h3>
Given that, in a two digit number,
t = the tens digit
u = the ones digit
The expression for the digit will be ,
10×t + u = 10t + u
The value of its reversal,
u = the tens digit
t = the ones digit
10×u + t = 10u + t is the required expression
For example,
37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3
Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.
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Answer:
250π
1000π
Step-by-step explanation:
(refer to attached)
volume of cylinder is given by:
V = π r²h,
where r = radius of base and h = height of cylinder
Given r = 5 and h = 10, hence
V = π r²h
V = π (5)²(10)
V = π (25) (10)
V = 250π (answer)
For the second case, r = 10 cm
V = π r²h
V = π (10)²(10)
V = π (100) (10)
V = 1000π (answer)
Answer:
2 inches by 3 inches by 6 inches and 2 inches by 2 inches by 4 inches
Step-by-step explanation:
Answer:
Step-by-step explanation:
The formula for the Newton's method is:
Where 
is the first derivative of the function evaluated in 
.
Lastly, the value of 
is determined by replacing 
with its numerical value:
Answer:
Jada should have multiplied both sides of the equation by 108.
Step-by-step explanation:
The question is incomplete. Find the complete question in the comment section.
Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:
Step 1: Multiply both sides of the equation by -9/4 as shown:
-4/9 × -9/4 = x/108 × -9/4
-36/-36 = -9x/432
1 = -9x/432
1 = -x/48
Cross multiplying
48 = -x
x = -48
It can also be solved like this:
Given -4/9 = x/108
Multiply both sides by 108 to have:
-4/9 * 108 = x/108 * 108
-4/9 * 108 = 108x/108
-432/9 = x
x = -48
Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.
