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3 years ago

A rectangle has a width of

Mathematics

1 answer:

hichkok12 [17]3 years ago

7 0

i think it would be 52cm

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State the slope-intercept form of the equation for the graph with the points 3,0 and 0,-1

Dvinal [7]

Answer:

The answer is y=1/3x-1

Step-by-step explanation:

m=1/3

y-y=m(x-x1)

y-(-1)=1/3(x-0)

y+1=1/3x-0

-1 -1

y=1/3x-1

6 0

3 years ago

The nine chips shown below are placed in a bag and then mixed up. Madeline draws one chip from this bag. What is the probability

babunello [35]

Complete question :

Image relating to the question can be found in the attachment below :

Answer:

4/9

Step-by-step explanation:

From the picture :

The nine chips are : 1, 2, 3, 4, 5, 6, 7, 8, 9

Even chips = 2, 4, 6, 8

Probability = number of required outcomes / (number of total possible outcomes)

Probability of drawing a chip with an even number :

P(even number) = number of even chips / total number of chips

P(even number) = 4 / 9

5 0

3 years ago

Which number produces a rational number when added to 1/5

marin [14]

Answer: 2/3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Currently a product has a gear ratio of 17:5, driver:driven. If the company wants to change the product to have the same gear ra

Sedbober [7]

Answer:

10 teeth must go on the driven gear

Step-by-step explanation:

Let the number of teeth be x

In order for the new product to maintain the same ratio as the old the ratio must remain the same. This means that

17:5 = 34:x

$\frac{17}{5} = \frac{34}{x}\\Now\ let\ us\ cross-multiply\\17 \times x = 5 \times 34\\17x = 170\\dividing\ both\ sides\ by\ 17 \\x = \frac{170}{17} \\x = 10$

∴ 10 teeth must go on the driven gear

hence ratio = 34:10

8 0

2 years ago

Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa

zimovet [89]

Answer:

$x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

Step-by-step explanation:

We are given that a quadratic equation

$x^2-x-1=0$

We have to solve the equation by completing square and find the value of b.

$(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0$

$(x-\frac{1}{2})^2-\frac{1}{4}-1=0$

$(x-\frac{1}{2})^2-\frac{1-4}{4}=0$

$(x-\frac{1}{2})-\frac{5}{4}=0$

$(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0$

$(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2$

$x-\frac{1}{2}=\frac{\sqrt5}{2}$ and $x-\frac{1}{2}=-\frac{\sqrt5}{2}$

$x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}$

And $x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}$

Therefore, $x=\frac{1+\sqrt5}{2}$ and $x=\frac{1-\sqrt5}{2}$

and b= $\frac{5}{4}$

6 0

3 years ago