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salantis [7]
3 years ago
6

The vertex of a quadratic function is located at (1, 4), and the y-intercept of the function is (0, 1). What is the value of a i

f the function is written in the form y = a(x – h)2 + k? a =
Mathematics
2 answers:
lidiya [134]3 years ago
9 0
The answer was -3, hope this helps you

Liula [17]3 years ago
9 0

Answer:

-3

Step-by-step explanation:

Edge

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Two increased by three equals the quotient of ten and two
RideAnS [48]
5 because increased by means to add 2+3
and quotient means the answer to a division problem 10/2 so ur answer is 5
4 0
3 years ago
Use the quadratic formula to find the roots of y = x2 + 5x + 6 :
Katena32 [7]

Answer: x = -2 and x = -3

Step-by-step explanation:

y = x^2 + 5x + 6 *FACTOR*

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x = -2

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    -3   -3

x = -3

7 0
3 years ago
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What is a possible value for the missing term of the geometric sequence?<br><br> 43, ___, 688, ...
Ostrovityanka [42]

Answer:

172

Step-by-step explanation:

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4 0
2 years ago
What is the range of y = (x - 5)^2 – 1?
Setler79 [48]

1.  The graph is a parabola.

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3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

8 0
3 years ago
(cos6x+6cos4x+15cos2x+10)/(cos5x+5cos3x+10cosx)=?
Tasya [4]
Do you mean <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x+5<span>cos3</span>x+10cosx</span></span>  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x+5cos3x+10cosx</span></span>  ?</span> or <span><span><span><span>cos6</span>x+6<span>cos4</span>x+15<span>cos2</span>x+10</span><span><span>cos5</span>x</span></span>+5<span>cos3</span>x+10cosx  ?</span> or <span><span><span>cos6x+6cos4x+15cos2x+10</span><span>cos5x</span></span>+5cos3x+10cosx  <span>?</span></span>
7 0
3 years ago
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