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2 years ago

Ok, I am so sorry ,I rlly don't understand any of these things , can y'all help me with

Mathematics

1 answer:

melomori [17]2 years ago

3 0

Answer:

x is 2.88 which can be rounded up to 2.9

Step-by-step explanation:

Subtract 2/3x from 5x.

Add 1/2 to 12.

Simplify and put into calculator (y=) to double check.

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

2 years ago

PLEASE HELP. I don’t get it at all and I’d really appreciate it. Thank you!

White raven [17]

Answer:

was this the whole question cause it depends on what the plane is

Step-by-step explanation:

3 0

1 year ago

6/8=y/16 how do you find the proportion of value y

Katarina [22]

You can set both fractions to have the same denominator by multiplying 6/8 (both the 6 and 8) by 2 to keep the value of the fraction, while turning the denominator to 16. So you get 12/16=y/16.
That means for the equation to be true y has to be 12.

Hope this helps!

4 0

3 years ago

Draw the two-dimensional shape<br> that makes up the faces of this<br> solid shape.

Art [367]

Answer:

like this?

Step-by-step explanation: