Find the first six terms of the sequence.
a1 = -7, an = 4 • an-1
2 answers:
Answer:
a1= -7
a2=4 <span>• -7= -28
a3=4 </span><span>• -28= -112
a4=4 </span>• -112= -448<span>
a5=4 </span>• -448= -1792<span>
a6=4 </span><span>• -1792= -7168</span>
A1 = -7
an = 4 * an-1
a2 = 4 * a(2-1) = 4 * a1 = 4 * -7 = -28
a3 = 4 * a(3-1) = 4 * a2 = 4 * -28 = -112
a4 = 4 * a(4-1) = 4 * a3 = 4 * -112 = -448
a5 = 4 * a(5-1) = 4 * a4 = 4 * -448 = -1,792
a6 = 4 * a(6-1) = 4 * a5 = 4 * -1792 = -7,168
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Hope this helps, have a good day
The first one because they go up by 4 each time thus it is linear.
Hope this helps! :)
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im pretty sure
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I think the third slot is even number
