Hello :
by idetity : 1+cos(2a) = 2cos²(a)
let : a = <span>θ/2
1+cos(2×</span>θ/2)=2cos²(θ/2)
1+cos(θ) = 2cos²(θ/2)
solve : 2 cos^2 (θ/2) - 3 cos(θ) = 0 ......(1)
(1) : 1+cos(θ)-3 cos(θ) =0
2cos(θ) = 1
cos(θ) = 1/2
in : [0, 2π<span>[
</span>( θ = π/3) or (θ = 5π/3)
Answer:
x = -2.3
Step-by-step explanation:
4x + 1.3 = -7.9
First we want to combine the like terms.
Subtract 1.3 from both sides.
4x = -9.2
Now we want to isolate x by dividing both sides by 4.
x = -2.3
Check your answer by plugging x back into the original equation.
4x + 1.3 = -7.9
4(-2.3) + 1.3 = -7.9
Multiply.
-9.2 + 1.3 = -7.9
Add.
-7.9 = -7/9
Your answer is correct.
Hope this helps!
Answer:
Step-by-step explanation:
To add fractions you need equal denominators
7/100+(1/10)(10/10)
7/100+10/100
17/100 (or 0.17 as a decimal)
1) 3
2) 8
3)10
4)-4
Hope this helped
Answer:
Step-by-step explanation:
Both 32 and 40 are divisible by 8.
32÷8=4
40÷8=5
Thus, the simplest form is
