V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
There's a bunch of them like if you simplify you could get 3/4.I'll give you some more.
Examples:14/16 21/24 28/32 and 35/40.
My brain was getting tired to think...but there's more.
Hope this helps :D
Answer:
A.
Step-by-step explanation:
We are given the two points (2,7) and (4,-1). In order to determine the linear equation, we need to find the slope and the y-intercept. First, find the slope <em>m.</em> Let (2,7) be x1 and y1, and let (4,-1) be x2 and y2:
Thus, the slope is -4.
Now, to find the y-intercept, we can use the point-slope form. Recall that the point slope form is:
Where (x1, y1) is a coordinate pair and m is the slope.
Use either of the two coordinate pair. I'm going to use (2,7). Substitute them for x1 and y1, respectively:
This is also slope-intercept form. The answer is A.
Answer:
Y = x - 9
Step-by-step explanation:
A slope of 1 = x
So we have
Y = x
To find y intercept we do
7 - (-2) = 9
So we have a y-intercept of 9
Y = x - 9
