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Nikitich [7]
3 years ago
12

A production process produces 5% defective parts. A sample of five parts from the production process is selected. What is the pr

obability that the sample contains exactly two defective parts
Mathematics
1 answer:
lapo4ka [179]3 years ago
5 0

Answer:

0.0214

Step-by-step explanation:

Given that :

p = 5% = 0.05

Number of trials (n) = 5

probability that the sample contains exactly two defective parts

P(x = 2)

Using the binomial probability function :

P(x = x) = nCr * p^x * (1 - p)^(n-x)

P(x = 2) = 5C2 * 0.05^2 * (0.95)^3

P(x = 2) = 5C2 * 0.05^2 * (0.95)^3

P(x = 2) = 10 * 0.0025 * 0.857375

= 0.021434375

= 0.0214

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<span>So let’s simplify the given situation.
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Since, it’s a combination of whole number and fraction; we cannot directly subtract this given equation. We need to convert the two given number into a fraction.
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Now, we have 2 fractions with unlike denominator. In order to get a common denominator, we have to find their least common factor.

=> <u>73</u> - <u>17  </u> = <u>73 x 6 </u> - <u>17 x 8 </u> <u>
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a recipe calls for 32 fluid ounces of heavy cream how many one pack of 2 days of heavy cream are needed to make the recipe
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