A production process produces 5% defective parts. A sample of five parts from the production process is selected. What is the pr obability that the sample contains exactly two defective parts
1 answer:
Answer:
0.0214
Step-by-step explanation:
Given that :
p = 5% = 0.05
Number of trials (n) = 5
probability that the sample contains exactly two defective parts
P(x = 2)
Using the binomial probability function :
P(x = x) = nCr * p^x * (1 - p)^(n-x)
P(x = 2) = 5C2 * 0.05^2 * (0.95)^3
P(x = 2) = 5C2 * 0.05^2 * (0.95)^3
P(x = 2) = 10 * 0.0025 * 0.857375
= 0.021434375
= 0.0214
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