Answer:
0.0214
Step-by-step explanation:
Given that :
p = 5% = 0.05
Number of trials (n) = 5
probability that the sample contains exactly two defective parts
P(x = 2)
Using the binomial probability function :
P(x = x) = nCr * p^x * (1 - p)^(n-x)
P(x = 2) = 5C2 * 0.05^2 * (0.95)^3
P(x = 2) = 10 * 0.0025 * 0.857375
= 0.021434375
= 0.0214
3x-x+2=4 :)
Hope this helped! :3
the answer would be 67,127 because the number in the ones would be 7 and the tens number would be 2 since it wouldn't more than 1.
67,102
67,135
1-7
67,127
7.69230%
R=I/P×T
R=$182/$700×2
R=182/1400
R=91/700
=7.69230%
